find the solution of the differential equation p2+y2=1
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Step-by-step explanation:
Given: p2+y2=1
To find: find the solution
Solution:
p2+y2=1
p.2+y.2=1
p2=1-y2
p2/2=1/2-y2/2
p=1-2y/2
or
y=2p+1/2
Hence,
the solution is
p=1-2y/2
or
y=2p+1/2
hope it helps you.
this one is complete and proper answer.
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