Question

Find the solution of the
differential equation
p² + y² = 1​

Answer 1

Answer:

Its too hard even I don't know the answer

Answer 2

for p= 0

p^2+y^2=1

o^2 + y^2 =1

y=√1

y=1

for p=1

p^2+y^2=1

1^2+y^2=1

y^2 = 1-1

y =√0 = 0

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