Question

find the solution of the equation 5p+2=17by trial and error method​

Answer 1

Step-by-step explanation:

According to the given question, we will use the trial and error method to solve the given equations.

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.S

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,5(1) + 2 = 7 ≠ 17

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,5(1) + 2 = 7 ≠ 17By putting, p = 2,

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,5(1) + 2 = 7 ≠ 17By putting, p = 2,5(2) + 2 = 12 ≠ R.H.S

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,5(1) + 2 = 7 ≠ 17By putting, p = 2,5(2) + 2 = 12 ≠ R.H.SBy putting, p = 3,

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,5(1) + 2 = 7 ≠ 17By putting, p = 2,5(2) + 2 = 12 ≠ R.H.SBy putting, p = 3,5(3) + 2 = 17 = R.H.S

According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.5p + 2 = L.H.SBy putting, p = 0,5(0) + 2 = 2 ≠ 17By putting, p =1,5(1) + 2 = 7 ≠ 17By putting, p = 2,5(2) + 2 = 12 ≠ R.H.SBy putting, p = 3,5(3) + 2 = 17 = R.H.STherefore, p = 3 is a solution of the equation.

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Answer 2

Answer:

HEY MATE

YOUR ANSWER:

5p+2=17

Put, p=0

5(0)+2=17

=> 2



=17

Put, p=1

5(1)+2=17

=> 7



=17

Put, p=2

5(2)+2=17

=> 12



=17

Put, p=3

5(3)+2=17

=> 17=17

Hence p=3

HOPE IT HELPS YOU!!

Step-by-step explanation:

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