Question

find the solution of the equation ax+b=0

Answer 1

$\textbf{Linear equation:}$

$\text{A polynomial equation in which the degree}\;$

$\text{of the variable is one is called Linear equation}\;$

$\textbf{Solution:}$

$\text{Solution of a polynomial equation in x is a real}$

$\text{value of x that satifies the polynomial equation}$

$\textbf{Given:}$

$a\,x+b=0$

$\textbf{To find:}$

$\text{Solution of a\,x+b=0 }$

$\text{Consider,}\;a\,x+b=0$

$\implies\,a\,x=-b$

$\implies\bf\,x=\dfrac{-b}{a}$

$\textbf{Verification:}$

$a\,x+b=0$

$a(\dfrac{-b}{a})+b=0$

$-b+b=0$

$0=0$

$\implies\text{ \dfrac{-b}{a} satisfies the given equation}$

$\therefore\textbf{The require solution is \bf\dfrac{-b}{a} }$

Answer 2

Answer:

Hey mate here is answer

ax+b=0

ax=b

x=-b/a

Step-by-step explanation:

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