Question

find the solution of the equation from the values of the variable given in the brackets. z+1=0(0,1,2 ,‐1)​

Answer 1

Answer:

(-1)=z

Step-by-step explanation:

Here as the various values are given,so it is preferable to do with trial method.

First we need to take the first value given i.e, 0 for z

So,

LHS,

z+1

Taking z as 0,

0+1=1

RHS,

0

So,

RHS is not equal to LHS

Now,

Let us take z as 1

z+1=1+1=2

Now also RHS is not equal to LHS

Let us now take z as 2

z+1=2+1=3

Still now,

RHS is not equal to LHS

Now z=(-1)

z+1=(-1)+1=0

So,

RHS=LHS

So,

(-1) is the value of z

OR

z+1=0

or, z=0-1

or, z=(-1)