Question

find the solution of the equation x2+x-(a+1) (a+2)=0​

Answer 1

Answer:

x^2-a^2+x-3a-2=0

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given x 2

+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x= 2a−b± b 2 −4ac = 2(1)−1± 1 2 −4{(a+2)(a+1)}

= 2−1±1−4{−(a 2 +3a+2)

x=2−1± 1+4a 2 +12a+8

= 2−1± 4a 2 +12a+9

= 2−1± (2a+3) 2

= 2−1±(2a+3)

∴x= 2−1+2a+3

and x= 2−1−2a−3

∴x= 2

2a+2

and x= 2−2a−4

x=a+1x=−(a+2)

∴ The roots of x 2

+x−(a+2)(a+1)=0 are (a+1) and −(a+2)