Find the solution of the equation
x2 + x -(a+1)(a +2) =0.
Answers
Answered by
0
Answer:
Given x
2
+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)
x=
2a
−b±
b
2
−4ac
=
2(1)
−1±
1
2
−4{(a+2)(a+1)}
=
2
−1±
1−4{−(a
2
+3a+2)
x=
2
−1±
1+4a
2
+12a+8
=
2
−1±
4a
2
+12a+9
=
2
−1±
(2a+3)
2
=
2
−1±(2a+3)
∴x=
2
−1+2a+3
and x=
2
−1−2a−3
∴x=
2
2a+2
and x=
2
−2a−4
x=a+1x=−(a+2)
∴ The roots of x
2
+x−(a+2)(a+1)=0 are (a+1) and −(a+2)
Step-by-step explanation:
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Answered by
2
Answer:
3x-a square+a+2a+2=0
3x-a square+3a=-2
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