Math, asked by pepalpop09, 3 days ago

find the solution of the equations x - y = 28 and x-3y = 0. find m such that y = mx-28​

Answers

Answered by hasinithirukovaluri
0

Answer:

X-y = 28.

X-y -28 = 0 (1)

X-3y = 0.

X-3y = 0 (2)

By elimination method

Subtract (1) from (2) equation

X-3y = 0

- (X-y-28)= 0

Then

X-3y = 0

-X+y+28=0

=. -2y+28=0

-2y = -28

y = 14

Put yvalue in equation 1

X-14-28 =0

X-42 =0

X=42

Put x and y value in y = mx + 5

14=42m+5

14-5=42m

9=42m

9/42=m

3/14=m

Step-by-step explanation:

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