Question

Find the solution of the equationx-4=2 by Trial and Error method​

Answer 1

using trial and error method

SUBSTITUTE X= - 4

LHS : - 4 + 4 ≠ RHS

SUBSITUE X = -3

LHS: -3 +4 =1 ≠RHS

SUBSITUE X=-2

LHS : -2 + 4 = 2=RHS

SORRY it took time

Answer 2

Answer:

  ∴ $x=6$ is the solution of given equation $x-4=2$.

Step-by-step explanation:

• In context to question asked,
• We have to find the solution of the equation $x-4=2$ by Trial and Error method​.
• So, put the value of $x=1,2,3,4,5,6...$ in the given equation.
• Now, put the value of $x=1$ in given equation, we get

         $x-4=2$

       ∴ $1-4=2$

         ∴ $-3\neq 2$

• Now, put the value of $x=2$ in given equation, we get

          $x-4=2$

       ∴ $2-4=2$

         ∴ $-2\neq 2$

• Now, put the value of $x=3$ in given equation, we get

          $x-4=2$

       ∴ $3-4=2$

         ∴ $-1\neq 2$

• Now, put the value of $x=4$ in given equation, we get

          $x-4=2$

       ∴ $4-4=2$

         ∴ $0\neq 2$

• Now, put the value of $x=5$ in given equation, we get

          $x-4=2$

       ∴ $5-4=2$

         ∴ $1\neq 2$

• Now, put the value of $x=6$ in given equation, we get

          $x-4=2$

       ∴ $6-4=2$

         ∴ $2= 2$

•   ∴ $x=6$ is the solution of given equation $x-4=2$.