Question

find the solution of the following pair is linear equations x+y=16,x-y=4 a) x=6,y=10 b) x=4,y=12 c) x=10,
y=6. d) x=10,y=5​

Answer 1

Step-by-step explanation:

x+y+x-y =16-4=12

2x=12

=6

y=16-6=10

x=6,y=10

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

Find the solution of the following pair is linear equations x + y = 16 , x - y = 4

a) x = 6 , y = 10

b) x = 4 , y = 12

c) x = 10, y = 6

d) x = 10 , y = 5

EVALUATION

Here the given pair of linear equations are

$\sf{ x + y = 16 \: \: \: \: \: \: .......(1)\: }$

$\sf{ x - y = 4 \: \: \: \: \: \: .......(2)\: }$

Adding Equation (1) & Equation (2) we get

$\sf{ 2x = 20\: \: \: \: \: \: }$

$\displaystyle \implies \sf{ x = \frac{20}{2} \: }$

$\displaystyle \implies \sf{ x = 10 \: }$

Putting the values of x in Equation (1) we get

$\sf{ 10 + y = 16\: }$

$\implies \sf{y = 16 - 10 \: }$

$\implies \sf{y = 6 \: }$

$\displaystyle \sf{Hence \: \: x = 10 \: \: \: and \: \: y = 6 \: \: }$

VERIFICATION

Putting x = 10 & y = 6 in both sides of Equation 1 we get

$\sf{ 10 + 6 = 16\: }$

$\implies \sf{ 16 = 16\: }$

Again Putting x = 10 & y = 6 in both sides of Equation 2 we get

$\sf{ 10 - 6 = 4\: }$

$\implies \sf{4 = 4}$

Hence verified

FINAL ANSWER

The solution of the following pair is linear equations x + y = 16 , x - y = 4

c) x = 10, y = 6

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