Question

find the solution of the following pair of linear equations.x+y= 16,x-y=4​

Answer 1

Question:-

find the solution of the following pair of linear equations.x+y= 16,x-y=4

Answer:-

• The required numbers are 10 and 6.

Solution:-

• x + y = 16 .........(1)
• x - y = 4 ............(2)

$\large{ : \implies \: x + y = 16}$

$\large{ : \implies \: x = 16 - y}$

Substitute value of x in eq 2.

$\large{ : \implies \: (16 - y) - y = 4}$

$\large{ : \implies \: 16 - 2y = 4}$

$\large{ : \implies \: - 2y = 4 - 16}$

$\large{ : \implies \: - 2y = - 12}$

$\large{ : \implies \: y = 6}$

Put value of y as 6 in eq 1

$\large{ : \implies \: x + 6 = 16}$

$\large{ : \implies \: x = 16 - 6}$

$\large{ : \implies \: x = 10}$

The required numbers are 10 and 6.

Answer 2

Answer:

(x+y) (x-y)

= (+16) (+4)

= {(16)²+(+4)²}

= {256+16}

= 272