find the solution of the following pair of linear eqution x+y=16,x-y=4
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x=10, &y=6......
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To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation
x+y=16,x−y=4
Choose one of the equations and solve it for xx by isolating xx on the left hand side of the equal sign.
x+y=16
Subtract yy from both sides of the equation.
x=−y+16
Substitute -y+16−y+16 for xx in the other equation, x-y=4x−y=4.
−y+16−y=4
Add -y−y to -y−y.
-2y+16=4
Subtract 1616 from both sides of the equation.
−2y=−12
Divide both sides by -2−2.
y=6
Substitute 66 for yy in x=-y+16x=−y+16. Because the resulting equation contains only one variable, you can solve for xx directly.
x=-6+16
Add 1616 to -6−6.
x=10
The system is now solved.
x=10,y=6
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