Question

find the solution of the following pair of liner equations x+y=16,x-y=4​

Answer 1

Answer:

We have x+3y=16 ..... (1)

2x−y=4 ...... (2)

Equation (1) becomes, x = 16 - 3y ...... (3)

Substituting x in (2) we get, 2(16−3y)−y=4

⇒32−6y−y=4

−6y−y=4−32

−7y=−28

y=

−7

−28

=4

Substituting y=4 in (3) we get, x=16−3(4)

=16−12=4

∴ The solution is x = 4 and y = 4.