Question

find the solution of the following pair of the liner equation x+y = 16, x-y = 4


A x=6,y=10
B x= 10,y= 6
C x= 10y= 5
D x=4,y=12​

Answer 1

$x + y = 16$

$x - y = 4$

SO

$16 + 4 = 20$

$\frac{20}{2} = 10$

$16 - 4 = 10$

$\frac{10}{2} = 5$

SO X = 10 AND Y = 6

HOPE IT HELPS TO U...#KEEPSMILE

Answer 2

x+y = 16------equuation (I)

x-y =4---------equation(ii)

we have to added both the equations.

x+y = 16

x-y = 4

—————

2x = 20

so, x= 10

Now, we have to put the value of x in equation (I)

x+y =16

10+y = 16

so, y = 16-10

y = 6

I hope it will help you.

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