Question

find the solution of the following pairof linear equation x+y=16,x-y=4

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Answer 1

Answer:

$1st \: pair \\ \implies x + y = 16 \\ \implies x = 16 - y$

$2nd \: pair \\ \implies x - y = 4 \\ \implies x = y + 4$

For this we got ,

$\implies x = 16 - y \\ \implies y + 4 = 16 - y \\ \implies y + y = 16 - 4 \\ \implies 2y = 12 \\ \implies y = \frac{12}{2} \\ \implies y = \frac{ \cancel{12}}{ \cancel{2}} \\ \implies y = 6$

From Equation 2 we get,

$\implies x = y + 4 \\ \implies x = 6 + 4 \\ \implies x = 10$

Therefore , Value of x is 10 and value of y is 6 .

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