Question

Find the solution of the given differential equation. (y + 4x + 2)dx – dy = 0, y(0) = 3

Answer 1

Answer:

(y+4x+2)dx-dy=0

Y(0)=3

Then,

(3+4x+2)dx-d(3)=0

(5+4x)dx-3d=0

4x*dx-3d= -5

dx5-12d= -5

dx5+5=12d

5=12d/dx5

5=12d/X5

By cross multiply

12d=5x5

d=5x5/12