Find the solution of the linear equation 8x+5y+32=0 which represents a point in
1. 2nd quadrant
2. 3rd quadrant
Answers
Given : linear equation 8x+5y+32=0
To find : solution that represents a point in 2nd quadrant & 3rd quadrant
Solution :
2nd Quadrant x is - ve & y is + ve
Hence taking magnitudes only
we can say
8(-x) + 5y + 32 = 0
=> 5y = 8x - 32
y > 0 if x > 4
Let say
x = 5
=> 5y = 8 => y = 1.6
=> x = -5 , y = 1.6 is one of the solution in 2nd Quadrant
x = -9 , y = 8 is also in 2nd Quadrant
(-5 , 1.6) & ( -9 , 8) solution in 2nd Quadrant
in 3rd Quadrant
x & y both are - ve
=> 8(-x) + 5(-y) + 32 = 0
=> 8x + 5y = 32
=> x = 1 , y = 4.8 also x = 2 , y = 3.2 , x = 3 , y = 1.6
hence (-1 , - 4.8) , (-2 , 3.2) , ( - 3 , -1.6) are few Solutions in 3rd Quadrant
(-5 , 1.6) & ( -9 , 8) few solution in 2nd Quadrant
(-1 , - 4.8) , (-2 , 3.2) , ( - 3 , -1.6) are few Solutions in 3rd Quadrant
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