Find the solution of the linear equation 8x+5y+32=0 which represents a point in
1. 2nd quadrant
2. 3rd quadrant
Answers
Given:
The linear equation 8x+5y+32=0 represents a point in
1. 2nd quadrant
2. 3rd quadrant
To find:
Find the solution of the given linear equation.
Solution:
From given, we have,
The linear equation 8x + 5y + 32 = 0 represents a point in
1. 2nd quadrant
2. 3rd quadrant
Now, consider, the linear equation represents a point in 2nd quadrant.
In the second quadrant, x is negative and y is positive.
So, we can re-write the equation as,
8(-x) + 5(y) + 32 = 0
-8x + 5y + 32 = 0 ........(1)
Now, consider, the linear equation represents a point in 3rd quadrant.
In the third quadrant, x is negative and y is negative.
So, we can re-write the equation as,
8(-x) + 5(-y) + 32 = 0
-8x - 5y + 32 = 0 ........(2)
solving equations (1) and (2), we get,
-10y = 0
∴ y = 0
substitute the value of y in equation (1), we get,
-8x + 5(0) + 32 = 0
-8x + 32 = 0
-8x = -32
∴ x = 4
Therefore, the solution of given linear equation is x = 4 and y = 0.