Math, asked by venkatasatvika1, 10 months ago

Find the solution of the linear equation 8x+5y+32 =0 which represents 2nd quadrant

Answers

Answered by Anonymous
21

The solutionof linear equation:-

•8x+5y+32=0

8x

=>8x+5y+32=0

=>8x+32= -5

=>4(2x+8)= -8y

Hope it's help you...✌️❤️

Answered by GSR9550
2

Answer:

x= -4 ,y =0

Step-by-step explanation:

In second quadrant y is positive and x is negative

x=-4 , y=0 will satisfy the condition

or x= -9 ,y= 8

or x = -4-5n , y= 8n to get a solution in second quadrant n should be any value greater than or equal to zero

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