Find the solution of the linear equation 8x+5y+32 =0 which represents 2nd quadrant
Answers
Answered by
21
The solutionof linear equation:-
•8x+5y+32=0
8x
=>8x+5y+32=0
=>8x+32= -5
=>4(2x+8)= -8y
Hope it's help you...✌️❤️
Answered by
2
Answer:
x= -4 ,y =0
Step-by-step explanation:
In second quadrant y is positive and x is negative
x=-4 , y=0 will satisfy the condition
or x= -9 ,y= 8
or x = -4-5n , y= 8n to get a solution in second quadrant n should be any value greater than or equal to zero
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