Find the solution of the linear equation x+2y-8=0 which represent a point on (a) X - axis (b) Y - axis
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Answered by
226
Hey there!
Here according to the question we need to find two solutions for the equation from which one lies on x - axis, and other on y- axis.
So a solution lies on x - axis, so y =0.
substitute y =0
x + 2 y -8=0
x + 2(0) -8=0
x -8=0
x = 8,
so the solution is (8,0).
a solution lies on y - axis. then x =0.
substitute x =0
x + 2y -8=0
0+ 2y -8=0
2y = 8
y = 4.
So the solution is (0,4).
==============<<>>===========
Therefore, (8,0),(0,4) are the solutions of x+2y-8=0 which represents a point on X - axis, Y - axis respectively
Here according to the question we need to find two solutions for the equation from which one lies on x - axis, and other on y- axis.
So a solution lies on x - axis, so y =0.
substitute y =0
x + 2 y -8=0
x + 2(0) -8=0
x -8=0
x = 8,
so the solution is (8,0).
a solution lies on y - axis. then x =0.
substitute x =0
x + 2y -8=0
0+ 2y -8=0
2y = 8
y = 4.
So the solution is (0,4).
==============<<>>===========
Therefore, (8,0),(0,4) are the solutions of x+2y-8=0 which represents a point on X - axis, Y - axis respectively
Answered by
64
heyy see attachment......
@randhawa#
@randhawa#
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