Question

find the solution of the pair of equation 4 / X + 3 Y = 8 and 6 / x minus 4 Y = - 5​

Answer 1

hope my answer helps you.

Answer 2

let 1/x = u

therefore.

4u+3y = 8...................(i)×3

6u-4y = -5.................(ii)×2

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12u+9y = 24

12u-8y =-10

(-) (+) (+)

_______________

17y = 34

y = 2

and substitue 'y' in eqn (i)

4u+3y = 8

4u+3(2) =8

4u = 8-6

u = 2/4

u= 1/2..

we know u = 1/x

1/2=1/x

x=2

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#hope it help u.

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