Question

find the solution of the pair of linear equation x+2y=5 and 7x+3y=13​

Answer 1

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x = 1

y = 2

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Answer 2

$\huge \sf \underline \red{Answer : }$

$\sf \underline \purple{ \therefore \: x = 1 \:, \: y = 2}$

$\huge \sf \underline \pink{To \: find : }$

• Solution of pair of linear equation

$\huge \sf \underline \blue{Solution : }$

$\sf {Given}\begin{cases}&\sf{\sf{x + 2y = 5.......(1)}\: } \\ \\ &\sf{\sf{7x + 3y = 13......(2)}\:} \\ \\ &\sf{\sf{this \: two \: are \: equations}}\end{cases}$

$\star \: \sf \underline{Now \: multiplying \: by \: 7(equation(1)})$

$\: \: \: \: \: \: \: \: \: \: \: \: \sf{7x + 14 y= 35.........(3)}$

$\sf \underline{Now \: we \: have \: to \: subtract \: eq(2) \: from \: eq(3)we \: get}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{11y = 22}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf{y = 2}$

$\star \: \sf \underline{putting \: y \: the \: value \: in \: eq(1) \: we \: get}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{x + 2(2) = 5}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{x = 5 - 4}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \sf \implies{x = 1}$

$\sf \underline{ \therefore \: x = 1 \:, \: y = 2}$