Question

find the solution of the quadratic equation 3/5x²-2/3x+1=0

Answer 1

HEY Buddy.....!! here is ur answer

Given that.... 3/5x²–2/3x+1 = 0

On taking LCM....

=> 9x²–10x+15 = 0

On comparing with the standard quadratic equation ax²+bc+c = 0

Here, a = 9, b = -10 and c = 15

According to the Shridharacharya Formula...

$x = \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x = \frac{10 \binom{ + }{ - } \sqrt{ {10}^{2} - 4 \times 9 \times 15 } }{2 \times 9} \\ \\ x = \frac{10 \binom{ + }{ - } \sqrt{100 - 540} }{18} \\ \\ x = \frac{10 \binom{ + }{ - } \sqrt{ - 440} }{18}$
So it is not able to solve ahead because there is negative sign under root

I hope it will be helpful for you....!!

THANK YOU ✌️✌️

MARK IT AS BRAINLIEST

Answer 2

Answer:

not real

3/5x²-2/3x+1=0