find the solution of the sum of two consecutive multiples of 11 is 77
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Answered by
2
Hey,
let the two consecutive numbers be ,
x and x+1
so as per the question !!
the sum of two consecutive numbers is 11
so , X + (X + 1) = 11
⇒ 2X + 1 = 11
⇒ 2X = 11 - 1
⇒ 2X = 10
⇒ X = 10 / 2
∵ X = 5
SO , the two consecutive numbers are
X = 5
and X + 1 = 6
HOPE IT HELPS YOU:-))
let the two consecutive numbers be ,
x and x+1
so as per the question !!
the sum of two consecutive numbers is 11
so , X + (X + 1) = 11
⇒ 2X + 1 = 11
⇒ 2X = 11 - 1
⇒ 2X = 10
⇒ X = 10 / 2
∵ X = 5
SO , the two consecutive numbers are
X = 5
and X + 1 = 6
HOPE IT HELPS YOU:-))
jotti:
I am very weak in maths
Answered by
1
let the two consecutive multiples are X and X+1 so
11*X+ 11(X+1) = 77
11( X+X+1) = 77
2x+1 = 7
X =3
x+1= 4
11*X+ 11(X+1) = 77
11( X+X+1) = 77
2x+1 = 7
X =3
x+1= 4
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