Question

find the solution of the sum of two consecutive multiples of 11 is 77

Answer 1

Let the two consecutive multiples of 11 be x and x+11 (because consecutive multiples of a number k differ by k)

Now x+(x+11) =77

⇒ 2x = 66

⇒x=33

So the numbers are 33 and 44 which are multiples of 11