find the solution of this problem
Answers
Step-by-step explanation:
Given:-
In ∆ABC, angle A = 3 angle B
and angle C = 2 angle B
To find:-
Find the all angles in the triangle ?
Solution :-
Given that
In ∆ABC, angle A = 3 angle B
=> ∠ A = 3 ∠B
=> ∠ A / ∠B = 3
=>∠ A / ∠ B = 3/1
=> ∠A : ∠ B = 3:1---------(1)
and
∠C = 2 ∠ B
=> ∠B /∠ C = 1/2
=>∠ B : ∠C = 1:2-----------(2)
∠A : ∠ B = 3:1
∠ B : ∠C = 1:2
_________________
∠A : ∠ B : ∠C = 3:1:2
_________________
Now Let be the angles 3X° ,X° and 2X°
The sum of all the three angles in a triangle is 180°
=> 3X°+X°+2X° = 180°
=> 6X° = 180°
=>X° = 180°/6
=>X° = 30°
=>3X° = 3×30°=90°
= 2X°=2×30°=60°
∠A = 90°
∠ B = 30°
∠C= 60°
Answer:-
The three angles in a triangle are 90°,30°,60°
Check:-
∠ A = 3 ∠B
90°=3×30°
∠C = 2 ∠ B
60°=2×30°
Verified the given relations.
Used formula:-
The sum of all the three angles in a triangle is 180°
Answer:
hope it helps plz mark as brainliest
Step-by-step explanation:
∠a = 3
∠b=2
∠c= 2
∵ we apply triangle sum property that is
sum of all ∠s = 180 degree
let the all three angles be 3x ,2x,2x
= 2x+2x+3x = 180
7x= 180
x=180/7
= 25.71
now ∠a = 3x= 25.71 x 3 == 77.14
∠b= 2x = 25.71 X 2 == 51.43
∠c= 2x = 25.71 X 2== 51.423