Question

find the solution of x+6/4+x-3/5=5x-4/8

Answer 1

GIVEN :

The equation is $\frac{x+6}{4}+\frac{x-3}{5}=\frac{5x-4}{8}$

TO FIND :

The solution of the given equation  $\frac{x+6}{4}+\frac{x-3}{5}=\frac{5x-4}{8}$

SOLUTION :

Given equation is  $\frac{x+6}{4}+\frac{x-3}{5}=\frac{5x-4}{8}$

$\frac{5(x+6)+4(x-3)}{20}=\frac{5x-4}{8}$

Now we have to find the solution for the given equation that is to find the value of x.

By using the Distributive property :

a(x+y)=ax+ay

$\frac{5(x)+5(6)+4(x)+4(-3)}{20}=\frac{5x-4}{8}$

$\frac{5x+30+4x-12}{20}=\frac{5x-4}{8}$

$\frac{9x+18}{20}=\frac{5x-4}{8}$

$9x+18=\frac{5x-4}{8}\times 20$

$9x+18=\frac{5x-4}{2}\times 5$

$(9x+18)\times 2=(5x-4)\times 5$

By using the Distributive property :

a(x+y)=ax+ay

$9x(2)+18(2)=5x(5)-4(5)$

$18x+36=25x-20$

$18x+36-25x+20=0$

Adding the like terms we get,

$-7x+56=0$

-7x=-56

$x=\frac{-56}{-7}$

$x=8$

∴ the value of x in the given equation is 8.

Answer 2

Answer:

x=8 is because the solution