Question

find the solution of x²+ 4 x + 8​

Answer 1

hey mate

here is your answer

i hope it helps you

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Answer 2

Hey mate!

Here's your answer!

x²+ 4 x + 8 = 0

We know that, (here +- is + or -)

$x = (- b + - \sqrt{b {}^{2} - 4ac }) \div 2a \\ = > ( - 4 + - \sqrt{(4) {}^{2} - 4 \times1 \times 8 }) \div 2 \times 1 \\ = > ( - 4 + - \sqrt{16 - 32} ) \div 2 \\ = > (- 4 + - \sqrt{ - 16}) \div 2 \\ >$

$= > ( - 4 + - 4i) \div 2$

Therefore, the solutions are (-4+4i)/2 and (-4-4i)/2. Simplifying them,

x = -2+2i, -2-2i

That's the answer!

Hope it helps :)