find the solution of x²-x¹+1=0
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Answer:
this is a q.eqn in x.
so,here a=1,b=-1,c=1.
x= -b-+-/(b²-4ac)
__________
2a
x=(1-+-/(1-4))/2
=(1-+-/(-3))/2
=(1-+-/3i)/2
so,the roots of x is (1+-/3i)/2,(1- -/3i)/2
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