Find the solution set of each of the inequition if replacement set is a whole number.
a) x<4
b)
![y \leqslant 12 y \leqslant 12](https://tex.z-dn.net/?f=y+%5Cleqslant+12)
c)
![0 < k \leqslant 8 0 < k \leqslant 8](https://tex.z-dn.net/?f=0+%26lt%3B+k+%5Cleqslant+8)
d)
![x - 1 \geqslant - 3 x - 1 \geqslant - 3](https://tex.z-dn.net/?f=x+-+1+%5Cgeqslant++-+3)
e)
![x + 3 > 0 x + 3 > 0](https://tex.z-dn.net/?f=x+%2B+3+%26gt%3B+0)
f)
![12 - 3x \geqslant 6 12 - 3x \geqslant 6](https://tex.z-dn.net/?f=12+-+3x+%5Cgeqslant+6)
g)
![3x + \geqslant 19 3x + \geqslant 19](https://tex.z-dn.net/?f=3x+%2B++%5Cgeqslant+19)
h)
![7 < 2x + 5 7 < 2x + 5](https://tex.z-dn.net/?f=7+%26lt%3B+2x+%2B+5)
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Answer:
a) 1+4» 5
b) 10-12» zjjsn 2
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