Question

find the solution set of the equation$5y^{2} +12y-9=0$

Answer 1

5y²+12y-9 = 0

5y²+15y - 3y -9 = 0

5y(y+3) - 3(y+3) = 0

(5y-3) ( y+3) = 0

5y-3 = 0 or y+3 = 0

5y = 3 or y = -3

y = 3/5 or y= -3