Question

Find the solution set of the inequation.​

Answer 1

$\sf{\cfrac{1}{3}\:(4x-1)+3\:≤\:4+\cfrac{2}{5}\:(6x+2),\:x\:∈\:Q} \\ \\ \\:\implies\sf{\cfrac{4x-1}{3}+3\:≤\:4+\cfrac{2\:(6x+2)}{5}} \\ \\ \\ :\implies\sf{20x-5+45\:≤\:60+36x+12} \\ \\ \\ :\implies\sf{20x+40\:≤\:72+36} \\ \\ \\ :\implies\sf{40-72\:≤\:36x-20x} \\ \\ \\ :\implies\sf{-32\:≤\:16x} \\ \\ \\ :\implies\sf{-2\:≤\:x} \\ \\ \\ :\implies\sf{x\:≥\:-2} \\ \\ \\ \therefore\sf{Solution\:set=\bigg\{x\:∈\:Q\::\:x\:≥\:-2\bigg\}}$