Question

Find the solutions by the method of completion of squares. 3x²+23x+20=0

Answer 1

Answer:

$3 {x }^{2} + 23 x + 20 = 0$

or,

$3( {x }^{2} + \frac{23x}{3} + \frac{20}{3}) = 0$

or,

or,

${x}^{2} + 2x \frac{23}{6} + \frac{23}{6} {}^{2} - \frac{23}{6} {}^{2} + \frac{20}{3} = 0$

or,

$(x + \frac{23}{6} ) {}^{2} - ( \frac{529}{36} - \frac{20}{3} ) = 0$

or,

$(x + \frac{23}{6} ) {}^{2} - ( \frac{17}{6}) {}^{2} = 0$

or,

$(x + \frac{50}{6} )(x + 1) = 0$

x=

$- \frac{50}{6}$

x=-1

Answer 2

Answer:

Step-by-step explanation: