Find the solutions of linear equation 2x + y = 4 which represents a point on (i) x-axis (ii) y-axis (iii)
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We have, x + 2y = 8 ,..(i) (i) When the point is on the X-axis, then put y = 0 in Eq. (i), we get x + 2 (0) = 8 => x = 8 Hence, the required point is (8, 0). (ii) When the point is on the Y-axis, then put x = 0 in Eq. (i), we get 0 + 2y = 8 => y = 8/2 = 4 Hence, the required point is (0, 4).
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