Question

find the solutions of x=10+3y and x=-30+7y

Answer 1

given , x=10+3y....... (1)

and x=-30+7y........ (2)

comparing equation (1) and (2)

10+3y=-30+7y

=>3y-7y=-30-10

=>-4y= -40

=>y = 10

therefore from equation (1),we get

x= 10+3×10

=>x=40

Answer 2

$10x + 3y = - 30 + 7y$

$3y - 7y = - 30 - 10$

$- 4y = - 40$

$y = 10$

then subsitute the value of y in equation 2

$x = - 30 + 7 \times 10$

$x = - 30 + 70$

$x = 40$

(x,y)=(10,40)---Ans

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