Math, asked by ritu9747, 2 months ago

find the solutions of x+2y+2z=2,3x-2y-z=5,2x-5y+3z=-4,x+4y+6z=0

Answers

Answered by dilnozayoldosheva27
0

Answer:

I think it has not got an answer

Step-by-step explanation:

x+2y+2z=2

3x-2y-z=5

4x+z=7

2x-5y+3z=-4   /*4

x+4y+6z=0    /*5

8x-20y+12z=-16

5x+20y+30z=0

13x+42z=16

4x+z=7  /*42

13x+42z=16

168x+42z=294

-156x=-278

x=1.78

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