Find the solutions of x²+5x+5=0 if x is rational no.
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hey friend
x²+5x+5=0
a=1; b=5; c=5
∆= b²-4ac= 25-4(1)(5)= 25-20=5
x= (-b±√∆)/2a
x=( -5±√5)/2
x=-5/2±√5/2
x=-5/2+√5/2. or x= -5/2-√5/2
x²+5x+5=0
a=1; b=5; c=5
∆= b²-4ac= 25-4(1)(5)= 25-20=5
x= (-b±√∆)/2a
x=( -5±√5)/2
x=-5/2±√5/2
x=-5/2+√5/2. or x= -5/2-√5/2
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