find the solutions set of x square + X - 12 less than equal zero
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Answered by
1
x²+x-12
=(x+4)(x-3)
=-4,3
hope it helps
Answered by
2
Answer:
Step-by-step explanation:
x² - x - 12
= x² - 4x + 3x - 12
= x(x-4) + 3(x-4)
= (x+3)(x-4)
x=-3/4
But here Solution Set is to be less than or equal to zero thus : it is -3 .
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