find the solve ,by substitution method;x+y=4; 3x_2y=_3
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Explanation
x + y =4
x=4 - y --------1
Now,
put x= 4 - y..
3x - 2y = - 3
3(4 - y) - 2y = - 3
12 - 5y = - 3
- 5y = - 3 - 12
-5y = - 15
y = 3.
Then, put y = 3 in enq 1..
x+y = 4
x + 3 = 4
x = 4 - 3
x = 1 ...
The solution set (x,y) is ( 1,3)
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