Find the some of all those natural numbers between 100 and 1000 which are completely divisible by 9.
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Answered by
1
1000-1=999
AND 108 IS SMALLEST
999-108=891
SO, 891/9 = 99
ANSWER IS 99
Answered by
2
1000-1=999 largest 3 digit number divisible by 9 100+8=108 smallest 3 digit number divisible by 9 999-108=891 891/9=99 There is another method If u ask the sum of all the no.s which are divisible by 9 from 100to1000 It will be 55350
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