Question

Find the son of a area of a right triangle whose base is 5cm and hypotenuse is 13cm​

Answer 1

Answer:

Consider the △ABC,

whereAC=13cm;BC=12cm by phythagorus theorm

AC

2

=AB

2

+BC

2

⇒AB

2

=AC

2

+BC

2

∴AB=

13

2

−12

2

=5cm

Area of △ABC=

2

1

×base×height

=

2

1

×AB×BC=

2

1

×12×5

=30cm

2

Answer 2

Answer:

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Step-by-step explanation:

According to the Pythagoras theorem :-

hypotenuse² = opposite side² + adjacent side²

=> 13² = opposite side² + 5²

=> opposite side² = 13² - 5²

=> opposite side² = 169 - 25

=> opposite side² = 144

=> opposite side = √144 = 12cm

Now we have base = 5 cm , height = 12 cm

Refer to image

Solution :-)

Using :-)

Area of the triangle = 1/2 x base x height

=> Area of the triangle = 1/2 x 5 x 12

=> Area of the triangle = 60/2

=> Area of the triangle = 30 cm²

Conclusion :-)

$\boxed {The \: area \:of \:the\: triangle \:= 30cm²}$