Question

find the soots of the
quacratic equation
x²+2x-3=0​

Answer 1

Step-by-step explanation:

X^2 + 2x - 3 = 0

X^2 - 3x + X - 3 = 0

X ( X - 3) + 1 ( X - 3) = 0

(X - 3) (X + 1) = 0

X = 3, - 1

Roots of the equation are 3 and - 1.

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