Question

find the soulution set by using method of cross multiplication 2y - 10x -86 =0 , 2x + 5y - 11 = 0 (please show detailed steps thank you )​

Answer 1

Answer:

2y -10x -86 =0

2y -10x = 86

2( y -5x ) = 86

y -5x = 43

y = 43 +5x _____(1)

substitute eqn (1) in 2x +5y -11 = 0

2x +5( 43 +5x ) -11 = 0

2x +215 +25x -11 =0

27x +204 =0

27x = -204

x = -204/27____(2)

substitute eqn 2 in eqn 1

y = 43 +5(-204/27)

y = 43 -1020/27

y = (1161 -1020) /27

y = 141/27

hence, we got, zero of the linear eqn in two variables is, (-204/27, 141/27)

Answer 2

Answer:

$\huge\pink{answer}$

Given, pair of equations is

2x+3y−7=0 and

6x+5y−11=0

By cross-multiplication method, we have

−33+35

x

=

−42+22

y

=

10−18

1

2

x

=

−20

y

=

−8

1

I II III

On taking I and III ratio, we get:

2

x

=

−8

1

x=

−4

1

On taking II and III ratio, we get:

−20

y

=

−8

1

y=

2

5

Step-by-step explanation:

hope it helps you