Question

Find the SP When
a) CP = 624 and Gain =30 1 by 3 %
b) CP = 6250 Loss=24%​

Answer 1

★ How to do :-

Here, we are given with the cost price and the gain percentage obtained in the first question. We are given that we should find the selling price of that sum. In the second question, we are given with the cost price and the loss percentage. We are asked to find the selling price of that sum. We are going to use the same formulas for both the questions, but in the place of gain it will be replaced by loss in the formula and in the place of addition sign, we should replace it with subtraction sign. So, let's solve!!

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➤ Formula required :-

${\tt \large \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{(100 + Gain \bf\%)}{100} \times SP}}}}$

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➤ Solution (1) :-

${\tt \leadsto \dfrac{(100 + 30.33)}{100} \times 624}$

${\tt \leadsto \dfrac{130.33}{100} \times 624 = \dfrac{13033}{10000} \times 624}$

${\tt \leadsto \dfrac{13033}{\cancel{10000}} \times \cancel{624} = \dfrac{13033}{2500} \times 156}$

${\tt \leadsto \dfrac{13033}{2500} \times 156 = \dfrac{13033}{625} \times 39}$

${\tt \leadsto \dfrac{13033 \times 39}{625} = \dfrac{508287}{625}}$

${\tt \leadsto \cancel \dfrac{508287}{625} = \boxed{\tt Rs \: \: 813.25}}$

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➤ Solution (2) :-

${\tt \leadsto \dfrac{(100 - 24)}{100} \times 6250}$

${\tt \leadsto \dfrac{76}{\cancel{100}} \times \cancel{6250} = \dfrac{76}{2} \times 125}$

${\tt \leadsto \dfrac{76 \times 125}{2} = \dfrac{9500}{2}}$

${\tt \leadsto \cancel \dfrac{9500}{2} = \boxed{\tt Rs \: \: 4750}}$

Hence solved!!

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$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Gain = S.P – C.P} \\ \\ \bigstar \:\sf{Loss = C.P – S.P} \\ \\ \bigstar \: \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{loss \: \% = \Bigg( \dfrac{loss}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{C.P =\dfrac{100}{100+Gain\%} \times S.P} \\ \\ \bigstar \: \sf{C.P =\dfrac{100}{100-loss\%} \times S.P}\end{array}}$