Question

find the specific gravity of a metal cylinder if weight of cylinder 352grams diameter of base 32mm height​

Answer 1

Answer:

Specific Gravity Formula

Specific gravity is a concept that we all have seen but do not know its name. Also, the density of the object determines this factor. Moreover, in this topic we will discuss specific gravity, specific gravity formula and its derivation and solved examples.

Specific gravity formula

Specific Gravity

Specific gravity refers to the ratio of the density of an object and the reference material. Furthermore, the specific gravity can tell us if the object will sink or float in reference material. Besides, the reference material is water that always has a density of 1 gram per cubic centimeter or 1 gram per millimeter.

In simple words, specific gravity defines whether an object will sink or float in water. Moreover, there are many factors that determine whether an object will float or sink.

Answer 2

Given:

Weight of cylinder (m) = 352g

Diameter of base  = 32mm

Height of cylinder= 32mm

To Find:

The specific gravity of the cylinder

Solution:

Specific gravity (also called the relative density) of a material is the ratio of the density of the material to the density of water.

or $S = \frac{d_m_a_t_e_r_i_a_l}{d_w_a_t_e_r}$

Density of material = Mass/Volume

= 0.352 kg / πr²h             (r = 32/2 mm)

= 0.352 kg/ 0.256 X 0.032 π m³

= 0.352/0.025 kg m⁻³

We know that density of water = 1000kg m⁻³

S= 0.352/0.025x1000 = 0.352 / 25

= 0.014

Hence, the specific gravity of cylinder is 0.014