find the specific heat capacity of iron if a 3kg piece of iron is supplied to 28.2k j of heat and it's temperatures rises by 20⁰c .step by step please
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Answer:
Explanation:
. c' = q/∆t
966 = q/15
q = 966*15=14490 j
2. c= q/m*∆t
c= 14490/ 2*15
c= 483 j/kg/k
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