find the specified term of each arithmetic sequence 10, -2, -14, ... the 17th term
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Answered by
1
Let the first term be a=10 ,
And common difference d= -12
:. 17th term = 10 + ( 17 -1 ) ( -12 )
=10 - (16×12)
=10 -192
= -182
Hope it helps you. . . .
And common difference d= -12
:. 17th term = 10 + ( 17 -1 ) ( -12 )
=10 - (16×12)
=10 -192
= -182
Hope it helps you. . . .
Answered by
0
First term => a => 10
Common Difference => d => -2 - 10 => -12
Hence,
17th term = a + 16d
= 10 + 16(-12)
= 10 - 192
= -182
Common Difference => d => -2 - 10 => -12
Hence,
17th term = a + 16d
= 10 + 16(-12)
= 10 - 192
= -182
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