Question

Find the speed of a ball dropped from a height of 80 m

Answer 1

Explanation:

Im assuming initial velocity is 0 and taking g as 9.8. Use the equation v sq. = u sq + 2gh. Velocity is 39.6 m/s.

Answer 2

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Given;

Distance(height)=80m

Acceleration(g)=10m/s²

Here, initial velocity=0m/s

Therefore, using equation 2nd of motion, s=ut+(1/2)at², we get;

80=(0)(t)+(1/2)(10)(t²)

=>80=(1/2)(10)(t²)

=>80=(5)(t²)

=>80/5=t²

=>16=t²

=>√16=t

=>4=t

Or, t=4s

Therefore, time taken by the object to reach the ground is 4 seconds.