Find the speed of a train which leaves Secundrabad at 7 p.m. and reaches Bhopal the next
day at 6 a.m. It stops for 1 hour on the way. The distance between Secundrabad and Bhopal
is 710 km. Also, find the average speed correct to one place of decimal.
Answers
Answered by
11
Answer:
Step-by-step explanation:
Distance = Speed/Time
710=x/10 (7pm to 6am = 11 hours . 1 hour halt=10hours)
Speed (x) = 710×10
Speed=7100km
Similar questions