Question

find the speed of a train which leaves secundrabad at 7 p.m and reaches Bhopal the next day at 6 A.m it stops for 1 hour in the way. the distance between sucendrabad and bhopal is 710 km. also find the average speed correct to one place of decimal.

Answer 1

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Answer 2

Answer:

Speed of the train = 64.54 km/ hr.

and,

Average Speed of the train = 59.16 km/hr.

Step-by-step explanation:

As the question is stated,

The time at which the train left the station of Secunderabad = 7 P.M.

Time at which the train reaches Bhopal = 6 A.M.

Time for which the train stopped = 1 hour

Distance between the Secunderabad and Bhopal = 710 km

Now,

Total time taken by the train = 11 hours of travelling time + 1 hour of rest time

So,

Speed of the train is given by,

$Speed=\frac{Distance}{Time}\\Speed=\frac{710}{11}\\Speed = 64.54\, km/hr.$

Because, the Speed is the ratio of the distance and the travelling time of the train.

Therefore, Speed of the train is 64.54 km/ hr.

Now,

Average Speed of the train is given by,

$Average\ Speed =\frac{Total\ Distance}{Total\ time}\\Average\ Speed = \frac{710}{12}\\Average\ Speed = 59.16\ km/hr.$

As, the Average speed of the train also includes the time for which the train rested.

Therefore, the Average Speed of the train is 59.16 km/hr.